Thanks Raul, your code helped me a lot to clarify my interpretation of the
problem!
I ended up using a recursive verb applying </. on the subset of path boxes
that weren't empty. It's not that elegant and there are still corners to
iron out. The reason why non-leaf nodes are rank 0 is because I have inputs
that should not be transformed and the 'path' for those is an empty box, so
I made the empty box a flag for a no-op (as in my 2nd example). If anyone
has suggestions for improvements though, I'd be very interested!
leaves =. 'g';1
paths =. (,0);1 0
mktree =: 3 : 0
'paths leaves' =. y
pathb =. (<'')&= paths
if. *./ pathb do. y return. end. NB.termination, nothing to modify
currl =. leaves #~ -. pathb NB.unfinished branches, modifications pending
finl =. pathb # leaves NB.final branches, nothing more to modify
k =. {.@> paths #~ -. pathb
modl =. k&(</.) L: 1 currl NB.modified leaves
nextl =. modl (I.@:-. pathb) } (# pathb) # <''
nextl =. finl (I. pathb) } nextl
nextp =. }. &.> paths
nextp ;< nextl
)
> L: 1 {: mktree^:_ paths;<leaves
leaves =. <'a'
paths =. <''
> L: 1 {: mktree^:_ paths;<leaves
Cheers,
Raoul
On Sat, Sep 19, 2020 at 7:08 PM Raul Miller <rauldmil...@gmail.com> wrote:
> I should have said: this isn't going to be all that efficient on large
> data structures.
>
> Efficiency on small data structures tends to be trivial (which has
> tended to yield lots of potentially misleading concepts and claims
> about efficiency in the popular press),
>
> Thanks,
>
> --
> Raul
>
> On Sat, Sep 19, 2020 at 1:05 PM Raul Miller <rauldmil...@gmail.com> wrote:
> >
> > Hmm...
> >
> > Would something like this fit what you are looking for?
> >
> > mktree=:1 :0
> > (0#a:) m mktree y
> > :
> > for_p. m do. path=.;p [ leaf=.p_index{::y
> > x=.path x insertnode leaf
> > end.x
> > )
> >
> > insertnode=:1 :0
> > :
> > len=. (#m)>.1+ndx=. {.x
> > if.1<#x do.
> > node=. (}.x) (ndx{::len{.m) insertnode y
> > else.
> > node=. y
> > end.
> > (<node) ({.x)} len{.m,a:
> > )
> >
> > leaves =. 'g';1
> > paths =. (,0);1 0
> > tree =. paths mktree leaves
> > tree -: 'g';<,<1
> > 1
> >
> > That's not quite the same as your original specification, but I can't
> > see any good reason to require that non-leaf nodes of the tree be rank
> > zero.
> >
> > Also, this isn't going to be all that efficient -- but (if this is
> > what you are looking for) there are some minor improvements available.
> >
> > Thanks,
> >
> > --
> > Raul
> >
> > On Sat, Sep 19, 2020 at 11:51 AM Raoul Schorer <raoul.scho...@gmail.com>
> wrote:
> > >
> > > Dear all,
> > >
> > > I am attempting to recover trees from a varying length path encoding.
> Chapter
> > > 32: Trees <https://www.jsoftware.com/help/learning/32.htm> shows how
> to do
> > > it for fixed-length paths, but I wasn't able to find a suitable
> solution to
> > > the varying length case. To illustrate:
> > >
> > > leaves =. 'g';1
> > > paths =. (,0);1 0
> > > tree =. paths mktree leaves
> > > tree -: 'g';<<1
> > > 1
> > >
> > > What would be the definition of 'mktree'? Is there a "common idiom" APL
> > > solution to that?
> > >
> > > Thanks a bunch,
> > > Raoul
> > > ----------------------------------------------------------------------
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> ----------------------------------------------------------------------
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