I just realized that I don't need Newton: 2/x + 4.9 = 0?
2/x = 49/10 2 = 49/10 * x x = 2/(49/10) = 2*(10/49) = 20/49 = 0.4081632653 Skip Cave Cave Consulting LLC On Sat, Oct 24, 2020 at 10:12 AM Skip Cave <[email protected]> wrote: > The Newton Raphson root finder using the new J definition of derivative is: > > N=: 1 : '- u % u deriv_jcalculus_ 1' > > > How would I use N to solve for x in the equation 2/x + 4.9 = 0? > > > Skip Cave > Cave Consulting LLC > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
