There's nothing wrong with that approach. But probably the most direct is (y+x*i=i.#y), and unless y is very long, this should be efficient.
-- Raul On Sun, Oct 25, 2020 at 3:58 AM pietdion <[email protected]> wrote: > > What is the best way to add, say, scalar x to component i of vector y? > > One way is (x + i{y) i} y > But this seems clumsy/expensive. > Is there a cleaner/more efficient way? > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
