To avoid breaking existing code that uses {{. .
Henry Rich
On 11/4/2020 11:07 AM, Raul Miller wrote:
Oh, yes.. hmm...
Looking at what I tested, I see that I messed up that test. (For some
reason, I just tested the ;: monad there.)
That said... remind me again why the {{ and }} rules do not follow the
same pattern as any other tokenization when dealing with . and :
characters?
Thanks,
--
Raul
On Wed, Nov 4, 2020 at 10:52 AM Henry Rich <[email protected]> wrote:
(0;sj;mj)&;: '{{.'
+---+
|{{.|
+---+
;: '{{.'
+-+--+
|{|{.|
+-+--+
(0;sj;mj)&;: 'NB. comment' , 10 48 10 { a.
+--------------+
|NB. comment 0 |
+--------------+
;: 'NB. comment' , 10 48 10 { a.
+-----------+-+-+-+
|NB. comment| |0| |
+-----------+-+-+-+
Henry Rich
On 11/4/2020 10:27 AM, Raul Miller wrote:
This needs more extensive testing, but I believe that I have an
updated mj and sj for
https://www.jsoftware.com/help/dictionary/d332.htm which delivers the
new behavior for the ;: monad with (0;sj;mj)&;:
(beware email induced line wrap).
mj=: 256$0 NB. X other
mj=: 1 (9,a.i.' ')}mj NB. S space and tab
mj=: 2 (,(a.i.'Aa')+/i.26)}mj NB. A A-Z a-z excluding N B
mj=: 3 (a.i.'N')}mj NB. N the letter N
mj=: 4 (a.i.'B')}mj NB. B the letter B
mj=: 5 (a.i.'0123456789_')}mj NB. 9 digits and _
mj=: 6 (a.i.'.')}mj NB. D .
mj=: 7 (a.i.':')}mj NB. C :
mj=: 8 (a.i.'''')}mj NB. Q quote
mj=: 9 (a.i.'{')}mj NB. {
mj=:10 (a.i.'}')}mj NB. }
sj=: _2]\"1 }.".;._2 (0 : 0)
' X S A N B 9 D C Q { } ']0
1 1 0 0 2 1 3 1 2 1 6 1 1 1 1 1 7 1 10 1 11 1 NB. 0 space
1 2 0 3 2 2 3 2 2 2 6 2 1 0 1 0 7 2 10 2 11 2 NB. 1 other
1 2 0 3 2 0 2 0 2 0 2 0 1 0 1 0 7 2 10 2 11 2 NB. 2 alp/num
1 2 0 3 2 0 2 0 4 0 2 0 1 0 1 0 7 2 10 2 11 2 NB. 3 N
1 2 0 3 2 0 2 0 2 0 2 0 5 0 1 0 7 2 10 2 11 2 NB. 4 NB
9 0 9 0 9 0 9 0 9 0 9 0 1 0 1 0 9 0 9 0 9 0 NB. 5 NB.
1 4 0 5 6 0 6 0 6 0 6 0 6 0 1 0 7 4 10 4 11 4 NB. 6 num
7 0 7 0 7 0 7 0 7 0 7 0 7 0 7 0 8 0 7 0 7 0 NB. 7 '
1 2 0 3 2 2 3 2 2 2 6 2 1 2 1 2 7 0 10 2 11 2 NB. 8 ''
9 0 9 0 9 0 9 0 9 0 9 0 9 0 9 0 9 0 9 0 9 0 NB. 9 comment
1 2 0 3 2 2 3 2 2 2 6 2 1 0 1 0 7 2 1 0 1 2 NB. 10 {
1 2 0 3 2 2 3 2 2 2 6 2 1 0 1 0 7 2 1 2 1 0 NB. 11 }
)
Thanks,
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