I was wondering about the rational for the choice of the cube root
returned for a negative number. I expected the real root to be returned,
e.g., (_8)^(%3) --> _2 but J gives 1j1.73205. This is the case in other
languages as well, so no doubt there is a mathematical justification for
this. In order to evaluate the solution of a cubic equation by Cardono's
formula, I had to define the cube root as:
cbrt=: {{ (*y)*(|y)^%3 }}
I just wonder why the default is for ^%3 to return a complex result.
Thanks,
Patrick
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