Well, on my screen the hexagon looks too tall and the y-axis has extremes
of (_0.4, 0.4) whereas the x-axis goes from _0.5 to 0.5, so it does not
look properly regular.

On Tue, Feb 9, 2021 at 4:19 PM 'Bo Jacoby' via Programming <
[email protected]> wrote:

>  Devon - 'aspect 1' plot 0.5*_1^3%~i.7 looks perfect!
>     Den tirsdag den 9. februar 2021 03.12.52 CET skrev Devon McCormick <
> [email protected]>:
>
>  Hauke - you are correct.  A hexagon can be thought of as six equilateral
> triangles.
> Bo - you are correct only for an unscaled hexagon.  See how "'aspect 1'
> plot 0.5*_1^3%~i.7" looks.
>
> Thanks everyone,
>
> Devon
>
> On Mon, Feb 8, 2021 at 8:53 AM 'Bo Jacoby' via Programming <
> [email protected]> wrote:
>
> >  'aspect 1'plot _1^3%~i.7
> >
> >
> >    Den mandag den 8. februar 2021 07.22.39 CET skrev Hauke Rehr <
> > [email protected]>:
> >
> >  The picture is Very Wrong™ (but the area formula is correct)
> > The lengths of the not-horizontal lines are interchanged.
> > And it looks distorted but that’s not too bad.
> >
> > And then it should be r =. sideOfUnitHexagon
> > which is obviously due to the same confusion
> > as the mislabelled lines.
> >
> > Just think of the hexagon cut into six triangles.
> > They’ll be regular as well, so radius = side.
> >
> > Another way to see this is to remember you can
> > construct a regular hex by taking a circle and
> > repeatedly go around that circle finding
> > intersections at one radius distance.
> >
> > Am 08.02.21 um 06:30 schrieb Devon McCormick:
> > > This scales the hexagon to have unit area.
> > >    hexagonArea=: 3 : '3*y*(-:y)*%:3'  NB. Where y is side length
> > >    sideOfUnitHexagon=: 0.6204032394013997
> > >    hexagonArea sideOfUnitHexagon
> > > 1
> > >    ]r=. sideOfUnitHexagon*-:%:3
> > > 0.537285
> > >    'title Regular Hexagons Centered at Origin;type line;pensize 2;
> aspect
> > > 0.866' plot (],.{."1) (r,1)*"(0 1) (_1^1r3)^i.6
> > >
> > > See
> > >
> >
> https://code.jsoftware.com/wiki/NYCJUG/2021-02-09#Corners_of_Unit_Hexagon_Centered_at_Origin
> > > for a diagram illustrating why we use the square root of 3.
> > >
> > > On Sun, Feb 7, 2021 at 4:00 PM Hauke Rehr <[email protected]>
> > wrote:
> > >
> > >> I wonder about that scaling factor in
> > >>
> > >>    */ , 5e_7 > | hexCorners - 0.537285 * +. (_1^1r3)^i.6
> > >>
> > >> Is there anything special about it?
> > >>
> > >>
> > >> Am 07.02.21 um 21:28 schrieb Devon McCormick:
> > >>> I'm trying to draw a unit hexagon centered at the origin with the
> > >>> horizontal sides parallel to the X-axis.  I've come up with these
> > >>> co-ordinates for the corners but when I plot them, the drawing looks
> a
> > >>> little too wide:
> > >>>
> > >>>    hexCorners=. _2]\,0.537285 0 0.268642 0.465302 _0.268642 0.465302
> > >>> _0.537285 0 _0.268642 _0.465302 0.268642 _0.465302
> > >>>    'title Regular Unit Hexagon Centered at Origin;type line;pensize
> 2'
> > >> plot
> > >>> (],{.) j./"1 hexCorners
> > >>>
> > >>> I can use my paint program to distort a picture of this plot until it
> > >> looks
> > >>> like it has a square aspect ratio (roughly, width height * 0.92 1.06)
> > but
> > >>> how can I plot this with the correct aspect ratio in the first place?
> > >>>
> > >>
> > >> --
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> > >>
> > >
> > >
> >
> > --
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> >
>
>
> --
>
> Devon McCormick, CFA
>
> Quantitative Consultant
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
>
> ----------------------------------------------------------------------
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>


-- 

Devon McCormick, CFA

Quantitative Consultant
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