does rank (f/)"(lr rr) help? lr for left rank, rr for right rank Am 22.02.21 um 22:46 schrieb Emir U: > I'm trying to table a function run with various parameters against data. The > function is in the form: x f y, where x are P parameters in a linked list, > and y is the data which has N rows. f has to be explicitly defined because > its complicated. > > Say X is Q different sets of parameters. I want to do: > > X f/ y > > and get a Q x N table where each cell represents the application of one > parameter set to one data row. > > Even if a use: > > f=: 4 : 0 '0' > > which definitely returns a scalar, the table verb doesn't seem to think its > rank 0 and won't behave as I'd like it to. > > I'd be grateful for some help on this. > > Emir > > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm >
-- ---------------------- mail written using NEO neo-layout.org ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
