AH - neat but wrong problem! Sorry.
Now for breakfast
M
On 21/03/2021 09:16, 'Michael Day' via Programming wrote:
I see Raul & Bob have replied while I was abed.
SO, before I look at their replies....
Not brute force, but quite neat:
<.^(10%3)*^.10
14
For a smaller problem, check with 4^4:
+/(=<.)^&(%3)>:i.4^4
6
<.^(4%3)*^.4
6
QED?
Cheers,
Mike
On 21/03/2021 02:57, Skip Cave wrote:
How do you solve this problem using J (brute force)
n =. >: i. 1000
p =. n^n
How many p are perfect cubes?
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