Henry's solution is easier, but with an added L:
;L:1 , { <("1) 3 2 $ <"0 'abcdef'
L: is similar enough to each, but directly operates at a boxing level rather
than unboxing then "undoing the unboxing" after
On Thursday, April 8, 2021, 04:10:06 p.m. EDT, Thomas Bulka
<[email protected]> wrote:
"'Pascal Jasmin' via Programming" <[email protected]> writes:
> , "0 1 /L:0("0 _)/ 3 2 $ <"0 'abcdef'
>
> assuming you don't need the boxes, but should be easy to transform if you
> insist.
Hi Pascal,
thanks for your solution, too. I'll study the use of L: in the
dictionary in some detail to get a better grasp of your idea.
Regards,
Thomas
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