Hi Harvey, the left argument to ‘from’ should be a single noun. In your
expression:
(2*j) (1+2*j) { ‘mevema'
You have
Noun1 Noun2 { Noun3
Which actually gives you s syntax error (N N V N)
You need:
Noun1 { Noun2
Since the left arg you want is 0 1, try this:
((2*j), (1+2*j)) { ‘mevema'
me
Or perhaps better:
(0 1+2*j) { 'mevema'
me
(0 1+2*j) evaluates to 0 1 as a single Noun.
Best, Rob
> On 13 Apr 2021, at 6:14 pm, HH PackRat <[email protected]> wrote:
>
> Hello, all!
>
> I'm stumped and need to know why the following "from" problem occurs
> and how to do what I'd like to do:
>
> No problem when numeric values are used:
> val=. 0 1 { 'mevema'
> me
> val=. 2 3 { 'mevema'
> ve
>
> Problem when formulas are used instead of numeric values:
> j=. 0 [or 1 or 2]
> val=. (2*j) (1+2*j) { 'mevema'
> |syntax error
> | val=. (2*j)(1+(2*j)){'mevema'
>
> Why does "from" work with numeric values but not with formulaic
> versions of those same values for use inside a "for_j" loop to handle
> multiple cases?
>
> What I'm trying to do is to grab 2 letters at a time in sequence
> through the 6-character combined planetary abbreviations for 3
> planets. Is there another way? (Explicit code only, please, if you
> give any examples.)
>
> I just don't understand why one version works and the other doesn't.
> Any help appreciated!
>
> Harvey
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