You might be interested in
https://www.jsoftware.com/help/dictionary/dpdot.htm or, in nuvoc
https://code.jsoftware.com/wiki/Vocabulary/pdot
Here's a quickie illustration:
,.1 {:: p. 1 (0 6)} 7#0
0.866025j0.5
0.866025j_0.5
0j1
0j_1
_0.866025j0.5
_0.866025j_0.5
I hope this helps,
--
Raul
On Sat, Oct 23, 2021 at 7:54 PM More Rice <[email protected]> wrote:
>
> Thank you for the notes - I'll keep it in my bookmark as reference!
>
> I started out this morning with my pre-calculus book trying to practice J
> sentences with. I wanted the numeric answers for complex roots. Like:
>
> // matlab version
> syms x
> eqn = x^6+1 == 0
> solve(eqn, x)
>
> But, it seems J only gives the principal root (?), not all 6 of them; so,
> another opportunity for practise. But, I ended up writing like ...
> "matlab":
>
> ^ 0j1 * (1p1 + 2p1 * i.6) % 6 NB. 1st version
>
> That was why I was browsing NuVoc, looking for examples/ideas, hoping to
> see something to make my J sentence looks more ... "J-idiomatic" (while
> learning something out of the process).
>
> This is all I can I come up with today:
>
> ^ 0j1 * 6 %~ 1p1 + 2p1 * i.6 NB. 2nd version
>
> How would the same answer look like in the eyes of J Masters?
>
>
> thanks for your thoughts.
>
> On Sat, Oct 23, 2021 at 4:18 PM 'Pascal Jasmin' via Programming <
> [email protected]> wrote:
>
> > a more hollistic explanation,
> >
> > Most conjunctions, and including the & and @ famillies, produce verb
> > phrases when bound. A verb or verb phrase can/has to produce different
> > results/computations depending on monadic or dyadic cases. In u@v, u is
> > always monadic, and v is ambivalent. in u&v, v is always monadic, and u is
> > the valence of the verb phrase.
> >
> > A missing "composing conjunction" in J is ([ u v) where u is always
> > dyadic and v is ambivalent. But the fact that it is easy to write as a
> > fork suggests a dedicated conjunction is not needed.
> >
> >
> > On Saturday, October 23, 2021, 03:30:09 p.m. EDT, Raul Miller <
> > [email protected]> wrote:
> >
> >
> >
> >
> >
> > https://www.jsoftware.com/help/dictionary/d631.htm
> >
> > x u&.v y ↔ vi (v x) u (v y)
> >
> > Here:
> > u is +
> > v is *:
> > vi is %: (or *:inv)
> > x is 3
> > y is 4
> >
> > So these are equivalent
> > 3 +&.*: 4
> > %: (*:3) + (*: 4)
> > *:inv (*:3) + (*: 4)
> >
> > I hope this makes sense.
> >
> > --
> > Raul
> >
> > On Sat, Oct 23, 2021 at 3:03 PM More Rice <[email protected]> wrote:
> > >
> > > Hello,
> > >
> > > (Sorry for the previous empty email - web page problem)
> > >
> > > please excuse another newbie question ...
> > >
> > > Ref: https://code.jsoftware.com/wiki/Vocabulary/starco
> > >
> > > pythag =: +&.*:
> > > 3 pythag 4
> > > 5
> > >
> > > + operated dyadically and acted on both x and y - ok.
> > >
> > > but how does *: know to act on x as well? Isn't pythag using the monadic
> > > definition of *: to square y only?
> > >
> > > so magical ...
> > >
> > > thank you for the pointer and have a great weekend.
> > >
> > >
> > > Maurice
> > > ----------------------------------------------------------------------
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> >
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> >
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