this should obviously have read u2@:v2@(u1&.:v1) ; u2@:v2&(u1&.:v1)
but feel free to use a different distribution scheme Am 04.12.21 um 15:17 schrieb Hauke Rehr:
u2@:v2@(u1&.:u2) ; u2@:v2&(u1&.:v1)
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