How about foo0`foo1`foo2`foo3 `:0 '' ? Am 02.04.22 um 19:42 schrieb Devon McCormick:
Hi, I have a group of monadic verbs for which I want the concatenated result, e.g. foo0=: 3 : '0' foo1=: 3 : '1' foo2=: 3 : '2' foo3=: 3 : '3' allfoo=: foo0,foo1,foo2,foo3 allfoo '' 0 1 2 3So *allfoo* does what I want. However, my actual set of verbs is longer than this so I broke the assignment of *allfoo* into two pieces for readability: allfoo=: foo0,foo1 allfoo=: allfoo,foo2,foo3 allfoo allfoo , foo2 , foo3 allfoo '' |stack error: foo3 |allfoo[0] I have inadvertently introduced infinite recursion. Clearly I'm missing something thinking I can concatenate verbs like I can concatenate nouns. This gives me a result that performs as expected but looks bad: allfoo=: foo0,foo1 allfoo=: (allfoo f.),foo2,foo3 allfoo'' 0 1 2 3 allfoo (3 : (,'0') , 3 : (,'1')) , foo2 , foo3 Any suggestions on how to break the assignment into multiple lines? Thanks, Devon
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