Your routine most likely doesn't do what you want it to:
'abc ' -: 0{:: (<@:])`(<@:".)"1 >'abc';'13.2'
1
The 'abc' got padded when you opened.
You could go for ]`(".&.>)"1. Or {{y 1}~ ".&.> 1{y}}. I don't expect you're
likely to find anything much nicer.
(Had j structural under, you might say ".&.(1&{::), but it does not.)
On Tue, 21 Feb 2023, Gilles Kirouac wrote:
I have two character strings :
datatype each 'abc';'13.2'
┌───────┬───────┐
│literal│literal│
└───────┴───────┘
I want to convert the second one into numerical data
datatype each (<@:])`(<@:".)"1 >'abc';'13.2'
┌───────┬────────┐
│literal│floating│
└───────┴────────┘
Can you simplify the above expression?
~ Gilles
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