J phrases is good source too.
https://www.jsoftware.com/docs/help807/phrases/rank_class.htm
On Fri, 17 Mar 2023 at 12:35 AM Devon McCormick <devon...@gmail.com> wrote:
> This is good to know - thanks!
>
> On Wed, Mar 15, 2023 at 8:40 PM Ric Sherlock <tikk...@gmail.com> wrote:
>
> > As an adverb we can get the ascending and descending by applying either
> /:
> > or \:
> >
> > open 'stats/base/univariate' NB. in JQt will open the script
> >
> > rankCompete=: 1 :'u~ i. ]'
> >
> > On Thu, Mar 16, 2023 at 1:30 PM Ric Sherlock <tikk...@gmail.com> wrote:
> >
> > > There are number of adverbs in the stats/base script for getting
> > different
> > > types of rankings
> > >
> > > NB.*rankOrdinal a ordinal ranking ("0 1 2 3") of array y
> > >
> > > NB.*rankCompete a standard competition ranking ("0 0 2 3") of array y
> > >
> > > NB.*rankDense a dense ranking ("0 0 1 2") of array y
> > >
> > > NB.*rankFractional a fractional ranking ("0 1.5 1.5 3") of array y
> > >
> > >
> > > \: rankCompete vec
> > >
> > > 6 0 3 0 4 2 5 6
> > >
> > > On Thu, Mar 16, 2023 at 11:24 AM Devon McCormick <devon...@gmail.com>
> > > wrote:
> > >
> > >> These are both way better than what I came up with. Thanks!
> > >>
> > >> On Wed, Mar 15, 2023 at 5:07 PM 'robert therriault' via Programming <
> > >> programm...@jsoftware.com> wrote:
> > >>
> > >> > Nicely done Elijah!
> > >> >
> > >> > It has a pretty solution in tacit as well
> > >> >
> > >> > vec=. 49 275 93 275 92 99 91 49
> > >> > t=. i.~ \:~
> > >> > t vec
> > >> > 6 0 3 0 4 2 5 6
> > >> >
> > >> > Cheers, bob
> > >> >
> > >> > > On Mar 15, 2023, at 13:59, Elijah Stone <elro...@elronnd.net>
> > wrote:
> > >> > >
> > >> > > One thing that comes to mind is (\:~vec) i.vec.
> > >> > >
> > >> > > On Wed, 15 Mar 2023, Devon McCormick wrote:
> > >> > >
> > >> > >> Hi, has anyone looked into how to generate a rank numbering where
> > >> > duplicate
> > >> > >> values get duplicate order numbers?
> > >> > >>
> > >> > >> For example, when we rank this vector descending,
> > >> > >> \:vec=. 49 275 93 275 92 99 91 49
> > >> > >> 1 3 5 2 4 6 0 7
> > >> > >> we see that 1 3{vec and 0 7{vec are the same so I would like to
> end
> > >> up
> > >> > with
> > >> > >> a rank numbering like this 6 0 3 0 4 2 5 6 so the ties for first
> > and
> > >> > last
> > >> > >> place get the same value in the proper order where zero
> designates
> > >> the
> > >> > >> highest.
> > >> > >>
> > >> > >> I know I've done this before and I have a very clumsy way to
> > achieve
> > >> > this
> > >> > >> but I'm wondering if there's a better one.
> > >> > >>
> > >> > >> Thanks,
> > >> > >>
> > >> > >> Devon
> > >> > >>
> > >> > >> --
> > >> > >>
> > >> > >> Devon McCormick, CFA
> > >> > >>
> > >> > >> Quantitative Consultant
> > >> > >>
> > >> ----------------------------------------------------------------------
> > >> > >> For information about J forums see
> > >> http://www.jsoftware.com/forums.htm
> > >> > >
> > ----------------------------------------------------------------------
> > >> > > For information about J forums see
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> > >> >
> > >> >
> ----------------------------------------------------------------------
> > >> > For information about J forums see
> > http://www.jsoftware.com/forums.htm
> > >> >
> > >>
> > >>
> > >> --
> > >>
> > >> Devon McCormick, CFA
> > >>
> > >> Quantitative Consultant
> > >> ----------------------------------------------------------------------
> > >> For information about J forums see
> http://www.jsoftware.com/forums.htm
> > >>
> > >
> > ----------------------------------------------------------------------
> > For information about J forums see http://www.jsoftware.com/forums.htm
> >
>
>
> --
>
> Devon McCormick, CFA
>
> Quantitative Consultant
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
>
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