Hi Devon -
Thanks for your help -- much appreciated.
I had a hunch when I saw this expression (%:n**:a).
But as part of it (n**:a) turned up as well in the calculation for (r')
I tackled the compound fraction using pen and paper
to make shure that formula was correct.
Then I changed the line for (f).
-Martin
At 2023-12-22 20:46, you wrote:
I tested the revised code and it works properly
for the examples, returning *_4
1 11;3 12* for *qcf 10 _1 _3 2* whereas the older version gives the same
result (*0;12 3*) for both *qcf 10 _1 _3 2* and *qcf 10 1 _3 2*.
I edited the body of *qcf* to remove the commented out line that Martin
revised since his change looks correct.
On Fri, Dec 22, 2023 at 2:42â¯PM Martin Kreuzer <i...@airkreuzer.com> wrote:
> Hi all -
> (This wasn't an easy one for me, as I still very much miss him.)
> I have been into CF for some time and re-read the essay this morning.
> It looks as there was a small glitch (maybe typo) in the body of function
> *qcf.
> May I ask you (having much more experience than me) to have a look at
> my edits as I do by no means want to spoil something.
> Many thanks.
> -Martin
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--
Devon McCormick, CFA
Quantitative Consultant
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