"Miller, Raul D" <[EMAIL PROTECTED]> writes:

> However: in the general case it is costly to find all eigenvectors.

That I believe.  In this case, I seem to have gotten all 4 quickly, so I
figured there shouldn't be much advantage in using another method just
to find the principal eigenvector unless there is a rather large
round-off error (I do understand that eigenvalue problems can be subject
to such problems).

Bill
-- 
Bill Harris                      http://facilitatedsystems.com/weblog/
Facilitated Systems                              Everett, WA 98208 USA
http://facilitatedsystems.com/                  phone: +1 425 337-5541

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