which matches the web reference I made
(http://www.rossi.com/sqr2.htm)... at least the first
2 lines of the maple result does.

If I understand the criticism of the web pasting I
made, it is that I only pasted approx 50 digits of the
solution, so I think the point was that even the right
50 digits is an innacurate approximation :(

--- John Randall <[EMAIL PROTECTED]>
wrote:

> Maple gives
> 
> > evalf(sqrt(2),503);
>
1.4142135623730950488016887242096980785696718753769480731766797379907324784\
>    
>
62107038850387534327641572735013846230912297024924836055850737212644121\
>    
>
49709993583141322266592750559275579995050115278206057147010955997160597\
>    
>
02745345968620147285174186408891986095523292304843087143214508397626036\
>    
>
27995251407989687253396546331808829640620615258352395054745750287759961\
>    
>
72983557522033753185701135437460340849884716038689997069900481503054402\
>    
>
77903164542478230684929369186215805784631115966687130130156185689872372\
>     353
> 
> Best,
> 
> John
> 
> Roger Hui wrote:
> > I wonder why you say "the number below is not
> correct either".
> > The following is a demonstration that  <[EMAIL PROTECTED]:
> 2x*10x^2*n  computes
> > the square root of 2 to n decimal places:
> >
> >    n=: 500
> >    s=: <[EMAIL PROTECTED]: 2x*10x^2*n
> >    $ ": s
> > 501
> >    _50 ,@(_5&(' '&,\))\ ": s
> >  14142 13562 37309 50488 01688 72420 96980 78569
> 67187 53769
> >  48073 17667 97379 90732 47846 21070 38850 38753
> 43276 41572
> >  73501 38462 30912 29702 49248 36055 85073 72126
> 44121 49709
> >  99358 31413 22266 59275 05592 75579 99505 01152
> 78206 05714
> >  70109 55997 16059 70274 53459 68620 14728 51741
> 86408 89198
> >  60955 23292 30484 30871 43214 50839 76260 36279
> 95251 40798
> >  96872 53396 54633 18088 29640 62061 52583 52395
> 05474 57502
> >  87759 96172 98355 75220 33753 18570 11354 37460
> 34084 98847
> >  16038 68999 70699 00481 50305 44027 79031 64542
> 47823 06849
> >  29369 18621 58057 84631 11596 66871 30130 15618
> 56898 72372
> >  3
> >
> >    ((i.20)&{"1 ,. ' ',. (495+i.20)&{"1) ": *: ,.
> s+_1 0 1
> > 19999999999999999999 99999567575656983330
> > 19999999999999999999 99999850418369457949
> > 20000000000000000000 00000133261081932568
> >
> > The last phrase demonstrate that s-1 is smaller
> than the square root,
> > but s+1 is larger.
> >
> > Perhaps those people with access to Mathematica or
> Maple can compute
> > the square root of 2 in those systems as a check.
> >
> >
> >
> > ----- Original Message -----
> > From: "Don Guinn" <[EMAIL PROTECTED]>
> > To: "Programming forum"
> <[email protected]>
> > Sent: Friday, March 10, 2006 4:52 PM
> > Subject: Re: [Jprogramming] More precision
> nightmares
> >
> > The answer you listed from the web is not correct.
>  It's correct only to
> > the number of digits listed.  The number below is
> not correct either,
> > but it's a lot closer.
> >
> >    0j200":(10x^500)%~(<[EMAIL PROTECTED]:)2x*10x^1000
> >
>
1.4142135623730950488016887242096980785696718753769480731766797379907324784621070388503875343276415727350138462309122970249248360558
> >
>
5073721264412149709993583141322266592750559275579995050115278206057147
> > ...
> >
> >
> >
>
----------------------------------------------------------------------
> > For information about J forums see
> http://www.jsoftware.com/forums.htm
> >
> 
> 
>
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> For information about J forums see
> http://www.jsoftware.com/forums.htm
> 


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