Yes, you should think of it as an unnamed primitive.  Same
for m&#.^:_1 .

#^:_1 can be used dyadically without requiring m&#^:_1 .
If you need a custom fill atom, #^:_1!.f , then you have to
add on the m& .

Henry Rich

> -----Original Message-----
> From: [EMAIL PROTECTED] 
> [mailto:[EMAIL PROTECTED] On Behalf Of Andrew Nikitin
> Sent: Wednesday, June 28, 2006 10:43 PM
> To: [email protected]
> Subject: [Jprogramming] #^:_1
> 
> 
> >From: Dan Bron <[EMAIL PROTECTED]>
> >
> >            1&#. b._1
> >     ($&1@>:@(1&(<[EMAIL PROTECTED]))@(1&>.)@(>./)@:|@, #: ]) :.(1&#.)
> 
> This one rings the bell. I could have just confuse the two.
> 
> So, the answer would be that bv&#^:_1 is an unnamed primitive?
> 
> 
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