2006/9/27, Henry Rich <[EMAIL PROTECTED]>: [snip]
h^:(]`(<:@[)`]) g
Yeah! That's it. I easily forget that there is the gerund cases for power, too. Thank you, Henry.
Henry Rich > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of > Yuvaraj Athur Raghuvir > Sent: Tuesday, September 26, 2006 11:45 PM > To: Programming forum > Subject: Re: [Jprogramming] Exploring Reflex & How to factor > out the argument > > By "pass the parameter y to the function f before it is > applied", I mean the > following effect - > (gy) (fy) (gy). > > Since I was trying to use the power function to repeat the > verb, I wanted to > control the number of times externally. For example, > > (gy) (h^:<:y) (gy) would then expand to : > > (gy) h (gy) .... (y-1) times... (gy) h (gy) > > So, I would like to define > f =. h^:<: > > Then I want to pass y to f to indicate number of application > of h between > (gy). > > ~Yuva > > p.s: In my example below, > h =. , > > > On 9/27/06, Roger Hui <[EMAIL PROTECTED]> wrote: > > > > (g y) f (g y) is indeed the same as (f~@:g) y > > > > What does "pass the parameter y to the function f > > before it is applied" mean? For example, does it > > mean y f (g y) ? > > > > (# ,:@i.) 5 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > (,~ $ i.) 5 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > (| i.@,~) 5 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > 0 1 2 3 4 > > > > > > > > ----- Original Message ----- > > From: Yuvaraj Athur Raghuvir <[EMAIL PROTECTED]> > > Date: Tuesday, September 26, 2006 8:10 pm > > Subject: [Jprogramming] Exploring Reflex & How to factor > out the argument > > > > > Hello, > > > > > > I am not sure if I understand the '~' (reflex) adverb right. > > > > > > 1) Is the following true? > > > (f~ @: g)y is the same as (gy) f (gy). > > > > > > 2) Now, I want to pass the parameter y to the function f > before it is > > > applied. Is that possible? > > > > > > Regards, > > > Yuva > > > > > > Example: (absolute beginner exploration...optimal versions are > > > welcome!) > > > NB. create a n by n matrix with 0 to (n-1) repeated n times > > > n =. 3 > > > NB. solution1: ravel the laminations n-1 times > > > (,: i.n) ,^: (<:n) (,: i.n) > > > 0 1 2 > > > 0 1 2 > > > 0 1 2 > > > NB. hmmm... looks like the n can be factored out... > > > NB. I see a reflex form, and then a power.... > > > NB. so, > > > sol1 =: (,^: (<:])~) @: (,: i.) > > > $ sol1 n > > > 2 3 4 3 > > > NB. Oops! The n has not reached the inner function. Is the form > > > right?? > > > NB. Another way using transpose.... > > > sol2 =. |: @: (#"0 i.)~ > > > sol2 n NB. works as intended > > > 0 1 2 > > > 0 1 2 > > > 0 1 2 > > > > > > > ---------------------------------------------------------------------- > > For information about J forums see > http://www.jsoftware.com/forums.htm > > > ---------------------------------------------------------------------- > For information about J forums see > http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
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