Raul,
Thank you very much. That clarifies your adverb within an
adverb to me. I did realize that the embedded adverb needed an
argument -- a: in your case -- to activate the verb.
On 10/23/06, Miller, Raul D <[EMAIL PROTECTED]> wrote:
Here's ident:
ident=:1 :'a:1 :(u b.1)'
The core of this statement is b.
According to the dictionary: 'u b. y gives ... the linear representation
of the identity function if y is 1'. For example:
+ b. 1
0 $~ [EMAIL PROTECTED]
But to be useful I need to convert this linear representation to
a verb. In ident, I'm using 1 :() to perform this conversion.
A simpler expression than ident might be
1 :(+ b. 1)
1 : '0 $~ [EMAIL PROTECTED]'
Except, I don't want an adverb, I want the verb, so I need to
throw an argument at it (which will be ignored) to get the
value the adverb produces
''1 :(+ b. 1)
0 $~ [EMAIL PROTECTED]
Now I have a verb. But I need to use 'u' in place of + so
that I can pass in the original verb I'm deriving from. Thus,
the original 1 :'a:1 :()' formulation.
Does that make sense?
Thanks,
--
Raul
--
(B=) <-----my sig
Brian Schott
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
