That's what I thought first, but since that
spot was taken, here's another one

   (b#x0) (I.b) } x1
0 8 2 10 4 12 6


--- Eldon Eller <[EMAIL PROTECTED]> wrote:

> Hows about this?
> 
>    b=.1 0 1 0 1 0 1
>    x0=.i.7
>    x1=.7+i.7
>    (b*x0)+(-.b)*x1
> 0 8 2 10 4 12 6
> 
> Leigh J. Halliwell wrote:
> > Thank you, Roger and Cliff.  On my first question I was indeed thinking of
> > the monadic amend.  And Cliff's use of it for my second question is nice,
> > too.  But I'd still like to know how to make the identity/left operator work
> > one-to one, as per my second question:
> >  
> > "2) X0 and X1 are numeric vectors, and B is a Boolean vector.  They all have
> > the same length.  I'd like to select from X0 where B is 0, and from X1 where
> > B is 1.  I try the expression: X1 [^:B X0.  But the adverb ^:B wants to get
> > two-dimensional, i.e., to apply each B to every pair of X1 and X2.  How can
> > I make J to apply the adverb one-to-one with the arguments?"
> >  
> > Sincerely,
> > Leigh
> >   
> > ------------------------------------------------------------------------
> >
> > ----------------------------------------------------------------------
> > For information about J forums see http://www.jsoftware.com/forums.htm
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
> 


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