> Also b&#^:_1 rather than b #^:_1 was mentioned, so that it does work without > the > & seems an extra bonus, is it reliable assuming fit is not needed?
x f^:n y is documented (on the same dictionary page you cited) as being equivalent to x&f^:n y which, with redundant parens inserted to make clear how it is parsed, is equivalent to ((x&f)^:n) y . Therefore, b #^:_1 y is the same as b&#^:_1 y . This was previously mentioned on the J Forum in an exchange between Henry Rich and myself. p.s. How is "extra bonus" different from "bonus"? Is it like a "free gift"? ----- Original Message ----- From: bill lam <[EMAIL PROTECTED]> Date: Friday, November 3, 2006 6:47 am Subject: Re: [Jprogramming] Boxing according to a Pattern > Thanks to Henry and Roger for help. > > it is written in system/extras/help/dictionary/d202n.htm > b&#^:_1 where b is a boolean list is Expand (whose fill atom f can > be specified > by fit, b&#^:_1!.f) > > I had read this page and this sentence before I asked, Why I > failed to notice > the portion inside parenthesis? (concentration dysfunction?) > > Also b&#^:_1 rather than b #^:_1 was mentioned, so that it does > work without the > & seems an extra bonus, is it reliable assuming fit is not needed? ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
