I now think my guess below about (&[)("_1) in k is
way off and instead (&[)("_1) in k is attaching to f=:2&^
or however f is defined.
On Sat, 25 Nov 2006, Brian Schott wrote:
+
+ c) to what is (&[)("_1) in k attaching itself or waiting
+ for or whatever? I guess the answer is the rest of l except
+ the amend, but I cannot see how.
+
(B=)
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