for your example
example=:0 :0
line 1
line 2
line 3
line 4
line 5
)
I think the result is like lisp:
(1
(2))
(3
(4))
(5)
I think the rule is if the line below is indented, you leave the current line's
parenthesis open. If the line below is outdented, then you add an extra
parentheses to close off your parent. If that line is outdented futher than
your immediate parent, then you close off that parent too and check one level
up.
That's what I'm looking for anyway. Is the problem easier by starting with S
expressions (above parenthesized form without white space)?
I'm having a hard time understanding your solution.
blocks=: [: +/\ ' ' ~: {."1
nest2=: <@{.`({. <@,&< (blocks $:/. ])@(}."[EMAIL PROTECTED]))@.({. <&('
'&[EMAIL PROTECTED]) {:)
nest2 [;._2 test
In the rhs to agenda, '({. <&(' '&[EMAIL PROTECTED]) {:)' I don't get why
comparing the head to the tail is relevant.
Its very impressive that you can keep track of what and where the dyads are in
that sentence, but that got me lost, even if comparing head and tail is
appropriate. Studying your code did make me understand an important
application of dyad &, but its overall too much of a stretch for me to fully
appreciate.
it doesn't quite match the spec:
sample =: (0{t),< (1{t), (2{t) , <( 3{t) , (< ( (4{t) ,<5{t )) , (<( 6{t), ( <
(7{t),< ( (8{t), 9 {t))), 10{t [ t =. ,. <"1@:(": ;. _2) test NB. all one line
test =: 0 : 0
html
head
body
p stuff
p div='adiv'
more stuff
table
tr
td 1
td 2
p last stuff
)
The only way I can think of implementing is recursive with a global variable
tracking across calls.
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