(*x)#^:_1(x#i.#x)</.y['x y'=:11 12 13 14 15; 3 0 2
|length error
|   (*x)#^:_1(x#i.#x)    </.y['x y'=:11 12 13 14 15;3 0 2

   x bx y
|length error: bx
|   x     bx y


R.E. Boss


-----Oorspronkelijk bericht-----
Van: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Namens Roger Hui
Verzonden: vrijdag 20 april 2007 2:21
Aan: Programming forum
Onderwerp: Re: [Jprogramming] Boxing Data

   (*x) #^:_1 (x#i.#x) </. y
+--------++-----+
|11 12 13||14 15|
+--------++-----+
   bx=: [EMAIL PROTECTED] #^:_1 ([EMAIL PROTECTED])@[ </. ]
   x bx y
+--------++-----+
|11 12 13||14 15|
+--------++-----+



----- Original Message -----
From: "Leigh J. Halliwell" <[EMAIL PROTECTED]>
Date: Thursday, April 19, 2007 5:02 pm
Subject: [Jprogramming] Boxing Data

> Dear J Forum:
> I want to box a vector of numbers and want to box according to another
> vector that tells how many to put in the boxes.  For example, 11 
> 12 13 14 15
> BoxAccTo 3 0 2 means (11 12 13); ace; (14 15).  It's important 
> that zeroes
> produce empty boxes.  Also, +/ of the second vector must equal # 
> of the
> first.
> I've created a tacit function that does the job.  However, I 
> suspect that
> it's inefficient.  In particular, it doesn't use the cut primitive 
> (;),because cut doesn't like boxing 0 elements.  So I hope that 
> you can come up
> with simpler, more efficient tacit functions.  
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