On 2007.08.31 16:47:16, you, the extraordinary Yuri Burger, emitted: > > how it works ??? > > p=:*&0.1 > p 10 > 1 > 1 p 10 > 1 > 2 p 10 > 0.1 > 3 p 10 > 0.01 > 4 p 10 > 0.001 > 5 p 10 > 0.0001 > > > > > (,&'-') '|' > |- > 2 (,&'-') '|' > |-- > 10 (,&'-') '|' > |----------
x (f&n) y <=> (f&n)^:x y but I can't quite see how that follows from what the Vocabulary says: The phrase x [EMAIL PROTECTED]&0 y is equivalent to f^:x y , apply the monad f x times to y . -- Nollaig MacKenzie http://www.yorku.ca/nollaig ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
