---Brian Schott wrote:
> Once I know how to define ndfr, then I want to create a
> binary mask from the result. For example if the I got the
> result 4 5 from ndfr 4r5 then I could produce the following
> mask (1 1 1 1 0), but I want the 1's and 0's more evenly
> distributed, like 1 1 0 1 1.
>
> (]{.#&[EMAIL PROTECTED])/4 5 NB. this produces an unbalanced result.
> 1 1 1 1 0
>
> From 7r10 I would like one of the following results.
>
> 1 1 0 1 1 0 1 1 0 1
> 1 0 1 1 0 1 1 0 1 1
>
> Ideas?
I'm sure there will be more elegant and tacit solutions, but in the
meantime this explicit verb seems to do the job.
bm=: 3 : 0
'n d'=. y
t=. >.n % >:d-n
d$(>:t) {. t#1
)
bm 4 5
1 1 0 1 1
bm 7 10
1 1 0 1 1 0 1 1 0 1
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