This looks like fails for singleton, atom or array.
R.E. Boss wrote:
0 1 (0 }:@, E.) 0 1 0 1 1 0 1 1 1 0 1 0
0 1 0 1 0 0 1 0 0 0 1 0
b=:1e6 [EMAIL PROTECTED] 2
(b > }: 0,b)-: 0 1 (0 }:@, E.) b
1
b=:i.0
(b > }: 0,b)-: 0 1 (0 }:@, E.) b
1
R.E. Boss
-----Oorspronkelijk bericht-----
Van: [EMAIL PROTECTED] [mailto:programming-
[EMAIL PROTECTED] Namens Roger Hui
Verzonden: woensdag 5 maart 2008 6:52
Aan: Programming forum
Onderwerp: Re: [Jprogramming] leading edge of a boolean array
Fails on the empty list. Likewise Oleg's solution.
(> 0 , }:) i.0
|length error
| (>0,}:)i.0
({. , 2 </\ ]) i.0
0
----- Original Message -----
From: Chris Burke <[EMAIL PROTECTED]>
Date: Tuesday, March 4, 2008 21:47
Subject: Re: [Jprogramming] leading edge of a boolean array
To: Programming forum <[email protected]>
Oleg Kobchenko wrote:
({. , 2 </\ ]) 0 1 0 1 1 0 1 1 1 0 1 0
0 1 0 1 0 0 1 0 0 0 1 0
--- bill lam <[EMAIL PROTECTED]> wrote:
how to find the leading edge of a boolean array,
eg. for this array
0 1 0 1 1 0 1 1 1 0 1 0
Also:
(> 0 , }:) 0 1 0 1 1 0 1 1 1 0 1 0
0 1 0 1 0 0 1 0 0 0 1 0
(defined as firstones in script parts).
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