Right again.   Your last case, of course, also can be simplified (and 
rewritten) as, 
 
 
   s_x_=: 1:
   do_x_ 'r=: s'
 
   r_x_ f.
|value error: s
|       r_x_ f.
   s=: ?
   (r_x_ -: r_x_ f.)0
0
   r_x_ 0
1
   r_x_ f.
?

----- Original Message ----
From: Raul Miller <[EMAIL PROTECTED]>
On Wed, Mar 5, 2008 at 12:10 PM, Jose Mario Quintana
<[EMAIL PROTECTED]> wrote:
> Right, this is essentially the "ridiculous" last answer (I should have 
> written the "ridiculously
> simple" answer) mentioned in the spoiler:

I believe you are refering to the first part of my response.

I further developed that example to illustrate a different case.
(That case should
probably be classified as a bug.)
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