You need f=: 3 : 'y * ?(#y)#0'2 3
because ?0 produces a scalar result. On Mon, Jun 30, 2008 at 10:46 AM, Benoît Roesslinger <[EMAIL PROTECTED]> wrote: > Hi, > > I am new to J and when doing some experiments with random number generation > I stumbled across the following behavior, which wasn't what I'd expect : > > f=: 3 : 'y * ?0' > f 3 > 2.91414 > f 3 > 0.139888 > f 3 > 0.990328 > > OK so far, but when I tried: > > f 3 3 > > it gives me : > > 0.0403801 0.0403801 (same values!) > > whereas I'd expect a behavior much like the one of '?'... > Is this behavior normal ? > Suppose I want to create a function to generate a random deviate from a > distribution (normal for instance) with some parameters (mean and sd for > instance) that will work in the same fashion as '?', ie it is possible to > generate lots of random deviates at once using code such as : distri 100 $ > x, where x would represent parameters, what is the best way to go ? > > Many thanks in advance! > > Benoît. > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > -- (B=) <-----my sig Brian Schott ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
