Very good.


----- Original Message -----
From: "R.E. Boss" <[EMAIL PROTECTED]>
Date: Thursday, September 18, 2008 9:09
Subject: RE: [Jprogramming] Verb Sequence or Ranking problem?
To: 'Programming forum' <[email protected]>

> 
>    (b(i.~ ~.) a){ 0,~ #/.~a
> 1 0 3 3 1 2 2
> 
> 
> R.E. Boss
> 
> 
> -----Oorspronkelijk bericht-----
> Van: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] Namens Alex Rufon
> Verzonden: donderdag 18 september 2008 16:39
> Aan: Programming forum
> Onderwerp: [Jprogramming] Verb Sequence or Ranking problem?
> 
> Hi.
> 
> I'm still at verb sequences and I have a question which I am guessing
> that is more of a rank solution.
> 
> I have the following values:
>    [a=: 1 1 2 2 3 5 5 5
> 1 1 2 2 3 5 5 5
>    [b=: 3 4 5 5 3 1 2
> 3 4 5 5 3 1 2
> 
> What I wanted to do was count the number of matching numbers in 
> a that
> are in b. So potentially, my result should be:
> 1 0 3 3 1 2 2
> 
> Which if I append to the b noun, I should get:
> 3 1
> 4 0
> 5 3
> 5 3
> 3 1
> 1 2
> 2 2
> 
> I can actually solve this by using a for loop but that's what 
> I'm trying
> to avoid. So I reasoned that I can count by each number like so:
>    #I. a e. 5
> 3
>    #I. a e. 4
> 0
> 
> Using verb sequencing, I can recode this as:
>    a [EMAIL PROTECTED]@e. 5
> 3
>    a [EMAIL PROTECTED]@e. 4
> 0
> 
> So far so good. Now this is where I hit a snag, I tried to use 
> the code
> above against b and I get the following:
>    a [EMAIL PROTECTED]@e. each b
> |length error
> |   a    [EMAIL PROTECTED]@e.each b
>    a [EMAIL PROTECTED]@e. ,.b
> 0
>    a [EMAIL PROTECTED]@e. every b
> |length error
> |   a    [EMAIL PROTECTED]@e.every b
>    
>    a [EMAIL PROTECTED]@e. "_ b
> 8
>    a [EMAIL PROTECTED]@e. "0 b
> |length error
> |   a    [EMAIL PROTECTED]@e."0 b
>    a [EMAIL PROTECTED]@e. "1 b
> 8
>    a [EMAIL PROTECTED]@e.@> (< every b)
> |length error
> |   a    [EMAIL PROTECTED]@e.@>(<every b)
>    a [EMAIL PROTECTED]@[EMAIL PROTECTED] (< every b)
> |syntax error
> |       [EMAIL PROTECTED]@[EMAIL PROTECTED](<every b)
>    
> So as you can see, I still have a long way to go. :(
> 
> r/Alex
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