> While fumbling around with base notation, I found > 5b34 > 19 > 5b35 > 20 > 5b36 > 21 > while I was waiting to see an error message for the second and third > case (using digits not in the set for this base, beyond 0 1 2 3 4). > This is puzzling me.
Seems consistent to me. 5b36 There are 6 "ones" (5^0) and 3 "fives" (5^1), that makes 21. Obviously you can get 21 using 5b41 too. --- Thanks, Ric & Devon... Let's take another example to make myself a bit more clear: 2b1010 10 2b2020 20 2b3030 30 I'm ready to admit that I can plainly see how this result is generated (as Ric pointed out); however I've never come across any binary integer of the form 2020 or 3030. So my question remains: is there a purpose that a function base-n (xby) will accept "foreign" digits without complaining..? --- avast! Antivirus: Outbound message clean. Virus Database (VPS): 090509-0, 09.05.2009 Tested on: 10.05.2009 07:21:15 avast! - copyright (c) 1988-2009 ALWIL Software. http://www.avast.com ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
