Dan Bron wrote: > How can I estimate the number of digits in !200e6 ?
Try Stirling's approximation. stirling=:(* ^.)-] log10=:(^. 10) %~ stirling 10^. !200x 374.897 log10 200 373.347 log10 200e6 1.57335e9 Best wishes, John ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
