2009/7/20 Sherlock, Ric <[email protected]>:
> Is there a reason that the 2nd one is not:
> (v0`v1`v2)} y   ↔       (v0 y) (v1 y)} (v2 y)

I have often wondered this myself, but this can be achieved with
v0`v1`v2}~ y

Unfortunately, this also typically requires v0, v1, and v2 all end
with @] which is rather verbose...

-- 
Raul
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