I have come across this before and solved it by explicitly referencing the verb
fun in the adverb:
cocurrent 'N1'
fun =: 3 : 0
2*y
)
A =: 1 : 0
u fun_N1_ y
)
cocurrent 'base'
*: A_N1_ 5
100
> From: Matthew Brand
>
> Thanks, will try it.
>
> Does anybody know a better solution though because this could lead to
> name clashes in a polluted z locale.
>
> 2009/9/15 bill lam:
> > On Tue, 15 Sep 2009, Matthew Brand wrote:
> >> Does anybody know how to make this work? I have an adverb A defined
> in
> >> a locale N1 which references the function "fun" which is also in
> that
> >> locale, but it is called from 'base' as A_N1_ ... How come it cannot
> >> find the verb "fun"? I expected the result to be 100, i.e. *: 2 * 5.
> I
> >> thought that J switched to the locale _N1_ and then executes the
> >> adverb?
> >>
> >> Thanks,
> >> Matthew.
> >>
> >> cocurrent 'N1'
> >>
> >> fun =: 3 : 0
> >> 2*y
> >> )
> >>
> >> A =: 1 : 0
> >> u fun y
> >> )
> >>
> >> cocurrent 'base'
> >> *: A_N1_ 5
> >> |value error: fun
> >> | u fun y
> >
> > I guess it is a design feature that automatic locale switching only
> > works for verb. You may try
> >
> > cocurrent 'base'
> > coinsert 'N1'
> > *: A 5
> >
> > or write the 'fun' in z locale
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