> From: Sherlock, Ric
> 
> > From: Raul Miller
> >
> > On Thu, Oct 15, 2009 at 4:58 PM, Eldon Eller wrote:
> > >   NB. stdval R returns the standard 1% resistor value nearest R.
> > >
> > > stdval=.10&^...@c*100&nrnd@(10&^@(96&(nrnd=.([:%[)*[:<.0.5"_+*)@(log-
> > c=.[:<.log=.10&^.)))
> > >
> 
> log=: 10&^.
> nrnd0=: [ %~ 0.5 <....@+ *
> stdval0=: <.&.log * 100 nrnd0 96 nrnd0 (- <.)&.log
> (stdval -: stdval0) 0.012 0.01 5 3 2
> 0
> 
> This seems to:
> log=: 10&^.
> nrnd1=: %...@[ * 0.5 <....@+ *
> stdval1=: (10&^@<. * 100 nrnd1 10 ^ 96 nrnd1 ] - <.)@log
>    (stdval -: stdval1) 0.012 0.01 5 3 2
> 1

Or using under (&.) as suggested by Raul
   stdval2=: (<.&.log * 100 nrnd1 (96 nrnd1 ] - <.)&.log)
   (stdval -: stdval2)  0.012 0.01 5 3 2
1

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