> Problem 2: How many of the !n permutations of even order n are
> solutions to problem 1?

Problem 2 probably does not have an easy solution
as the sequence 2 8 48 1152 34560 (for n=2 4 6 8 10)
is not a subsequence in the Online Encyclopedia of
Integer Sequences.

http://www.research.att.com/~njas/sequences/index.html

   +/ (2 comb n)&-:@pairs@(A.&(i.n))"0 i.!n=: 2
2
   +/ (2 comb n)&-:@pairs@(A.&(i.n))"0 i.!n=: 4
8
   +/ (2 comb n)&-:@pairs@(A.&(i.n))"0 i.!n=: 6
48
...



----- Original Message -----
From: Roger Hui <[email protected]>
Date: Wednesday, November 11, 2009 11:03
Subject: Re: [Jprogramming] APWJ exercises for the reader [1 of 4]
To: Programming forum <[email protected]>

> Solution to Problem 1:
> 
> magicperm=: C. @ < @ (|.@:>: , }.) @ (i.&.-:)
> 
>    magicperm 2
> 0 1
>    magicperm 4
> 0 2 3 1
>    magicperm 6
> 0 2 4 1 5 3
>    magicperm 8
> 0 2 4 1 6 3 7 5
> 
> Check:
> 
> seq  =: 3 : 'y {^:(}:i.#y) i.#y'
> pairs=: /:~ @ (>/"1 |."_1 ]) @ (_2 ]\ ,@seq)
> NB. comb from  http://www.jsoftware.com/help/dictionary/cfor.htm
> 
>    (2&comb -: pa...@magicperm)"0 }. 2*i.8
> 1 1 1 1 1 1 1
> 
> 
> 
> ----- Original Message -----
> From: Ian Clark <[email protected]>
> Date: Wednesday, November 11, 2009 3:56
> Subject: [Jprogramming] APWJ exercises for the reader [1 of 4]
> To: Programming forum <[email protected]>
> 
> > In At Play With J Edn 1, there were 4 questions left as 
> > exercises for
> > the reader. In Edn 2 we want to provide the answers in an Appendix.
> > 
> > Just so I don't get them wrong, could the forum please suggest what
> > the answers should be? You may have to refer to the Wiki page.
> > 
> > I'm putting each question in a separate thread.
> > 
> > +++++
> > In Chapter 5 Jacobi's method
> > http://www.jsoftware.com/jwiki/Doc/Articles/Play113 [see midway]
> > 
> > "Problem 1: Define a verb which takes as argument a positive even
> > integer n and yields a permutation which, repeatedly applied 
> to a
> > conforming identity permutation, produces, in successive pairs of
> > items, all possible choices of 2 items from n, with no duplications.
> > 
> > Problem 2: How many of the !n permutations of even order n are
> > solutions to problem 1?"
> > +++++
> > 
> > Ian Clark
> > Subeditor, APWJ Edn 2
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