On Sun, Nov 22, 2009 at 8:32 PM, Dan Bron <j...@bron.us> wrote:
> int result = 0;
> for (int i = 0; i < array.size; i++)
> {
> result *= array[i]
> }
>
> vs
> */ array NB. Even handles integer
> overflow!
>
>
> Which of the two are easier to compare? Did you spot the change in the
> second pseudocode? How about the 2 errors?
I only see one error (the first line).
> int[] result = int[math.ceiling( ((float) array.size) / 2.0)];
> for(int i = 0; i < array.size; i+=2)
> {
> result[i] = array[i]+array[i+1];
> }
>
> vs
>
> 2 +/\ array
You were thinking of _2 +/\ array. For 2 +/\ array you would want
int[] r= int[array.size-1]
for (int j= 0; j < array.size; j++)
r[j]= array[j]+array[j+1]
Though, properly speaking, you use "double" instead of "int"
when casting J into C.
--
Raul
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