b is recursively boxed.

   b=._3];._3 ] ,1 2 3
   b
3 2 1
   b=._3];._3 ] ,1 2
   datatype b
boxed
   datatype b
boxed
   datatype >b
boxed
   datatype >>b
boxed
   datatype >>>b
boxed


On Fri, Jan 15, 2010 at 4:17 AM, June Kim <[email protected]> wrote:
>   b=.1];._3 ''
>   b
>   ''-:b
> 1
>   (<'')-:b
> 0
>   4{.''
>
>   4{.b
> +++++
> |||||
> +++++
>   (4{.'')-:4{.b
> 0
>
> Why is the result of 4{.b boxed here? I think it shouldn't be boxed.
> Is this a bug?
>
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