Ooops, scratch the question below, silly me, just saw what's happening
there, i.e. 'N -  i.M'   rather than  'N (-i.) M'
but, if anything, this makes the grammatical breakdown of 
  14 */ @ (-i.) 3
a bit trickier...

On Thu, 2010-02-18 at 19:20 +0000, Alex Gian wrote:

> For, instance I can see that
> that  14(-i.)3 will give 14 13 12 
> (where is this documented? I also discovered [by chance] that 'n +i.
m'
> will give ascending ranges for integer m, n). 




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