> From: Alex Gian
>
> Things are a little less clear when trying the full tacit
> implementation
> Why does (*/ @ (-i.)) not behave as a fork?
Before you look for trains, first you have to identify the component verbs in
the phrase (i.e. resolve the adverbs and conjunctions).
(-i.) NB. is a verb formed by a two verb train (a hook)
*/ NB. is a verb formed by the adverb / and the verb to its left *
@ NB. is a conjunction that takes the verbs to its left and right to
form a new verb
So */@(-i.) is a single compound verb of the form f...@g and contains no fork.
The various display forms available can be useful in determining how the phrase
is parsed.
*/@(-i.)
NB. Boxed:
+-----+-+------+
|+-+-+|@|+-+--+|
||*|/|| ||-|i.||
|+-+-+| |+-+--+|
+-----+-+------+
The boxed format doesn't help you determine whether you are looking at a
compound verb or a train. The only way to tell is if you know that @ is a
conjunction. The Tree form gives you more of a hint about how the parts of
speech are affecting parsing (the displays are clearer using the box-drawing
symbols but they aren't very reliable in email):
NB. Tree:
+- / --- *
|
-- @ -+ +- --
+-----+- i.
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