,/ is recognized by the interpreter and is implemented by special code; ,~/ is not.
----- Original Message ----- From: gary ng <[email protected]> Date: Wednesday, March 3, 2010 21:58 Subject: [Jprogramming] newbie question about u/ y To: Programming forum <[email protected]> > As far as I can tell > > u/ y <=> foldr1 u y (in Haskell). > > -/ i.4 => -2 > > foldr1 (-) [0..3] => -2 > > I can also do foldl1 as u~/ > > What I don't understand is the speed difference(huge) between > > ,/ i.1000000 > > and > > ,~/ i.1000000 ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
