Raul,
Yes, your 1+F does seem to produce results identical to Idotr and Ier
behaves as you suggest. But look at the following experiments which
suggest that the difference is a little more subtle as suggested by
the final example.
2 3 5 (Idotr,:Ier) 0 1 2 3 4 5 6 7
0 0 1 2 2 3 3 3
0 0 1 2 2 3 3 3
2 3 5 (Idotr,:Ier) 0 1 2 3 4 5 6 7+0.5
0 0 1 2 2 3 3 3
0 1 2 2 3 3 3 3
(2 3 5+0.5) (Idotr,:Ier) 0 1 2 3 4 5 6 7
0 0 0 1 2 2 3 3
0 0 1 2 2 3 3 3
2 3 5 (Idotr,:Ier)&(+&0.5)] 0 1 2 3 4 5 6 7
0 0 1 2 2 3 3 3
0 0 1 2 2 3 3 3
Regarding your idea to replace >: with epsilon, that is intriguing,
but I have not had an opportunity to study it.
Thanks very much for your comments.
Do you think the pair of I.'s in F could be made more efficiently
calculated to require a single calculation? Years ago, I believe it
was Henry who showed me how such an efficiency can be accomplished in
simpler verb trains.
On Tue, Mar 16, 2010 at 5:26 PM, Raul Miller <[email protected]> wrote:
> On Tue, Mar 16, 2010 at 5:03 PM, Raul Miller
<[email protected]> wrote:
>
> For a floating domain replace >: with an operation
> which adds epsilon to the right argument. But your
> sample data on your histogram page was integer.
>
> FYI,
>
> --
> Raul
--
(B=)
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