Hi list, I am currently learning / experimenting with gerunds and made this very simple snippet that returns 1 if x >= 0, or 0 otherwise
0: ` 1: @. (0&<:) &> i:10 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 now lets say I wanted to return 64 instead of 1 0: ` 64: @. (0&<:) &> i:10 |spelling error | 0: ` 64: @. (0&<:) &> i:10 | ok, that's because 64: is not a j verb, so how about.. 0: ` (2^6) @. (0&<:) &> i:10 |domain error | 0:`(2^6)@.(0&<:)&>i:10 ok, that's because (2^6) is not a function, so what about.. 0: ` (2:^6:) @. (0&<:) &> i:10 0 0 0 0 0 0 0 0 0 0 64 64 64 64 64 64 64 64 64 64 64 ok, that was simple enough, so lets try 33 0: ` (3:+3:*2:*5:) @. (0&<:) &> i:10 0 0 0 0 0 0 0 0 0 0 33 33 33 33 33 33 33 33 33 33 33 this is starting to become ugly. I could easily write an explicit verb to give me the answer I am looking for - but I am not particularly looking to make explicit verbs thirty3=. 3 : '33' 0: ` thirty3 @. (0&<:) &> i:10 I am just wondering if I am missing something obvious? Thanks ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
