Cool, thanks!
So what about if you wanted to replace more than one character?
e.g.
Replace every occurrence of 'ab' with 'cd' in a string?
('ab';'cd') charsub 'abhello'
gives a length error. I tried with 'rplc' but I haven't quite figured out
the right way to pass arguments to that function yet
On 13 July 2010 14:02, Alex Rufon <[email protected]> wrote:
> Hi Mark,
>
> As Don suggested, for this one, the standard library is your friend. :)
>
> load 'strings'
> ('a';'x') charsub 'abcdefgabcdefg'
> xbcdefgxbcdefg
> (LF;',') charsub 'abcd',LF,'asdfasd',LF,'asdfasdf'
> abcd,asdfasd,asdfasdf
>
> r/Alex
>
> On Jul 13, 2010, at 8:46 PM, Don Guinn wrote:
>
> > This is one way.
> >
> > y=.'abc',LF,'de',LF,'f'
> > y=LF
> > 0 0 0 1 0 0 1 0
> > I.y=LF
> > 3 6
> > ','(I.y=LF)}y
> > abc,de,f
> >
> > Look at 'system\main\strings.ijs' for several tools for manipulating
> > strings.
> >
> > On Tue, Jul 13, 2010 at 6:31 AM, Mark Needham <[email protected]>
> wrote:
> >
> >> Hey,
> >>
> >> I can't work out where in the primer I need to look to work out how to
> do
> >> this so I figured I can post it here and someone can point me to the
> right
> >> place.
> >>
> >> I want to replace any new line '\n' characters in a string with a comma
> >> ','.
> >>
> >> My truly horrific imperative solution looks like this:
> >>
> >> replaceNewLines =: 3 : 0
> >> i =. 0
> >> newY =. ''
> >> while. i < # y do.
> >> if. i { y = '\' do.
> >> if. (i+1) { y = 'n'
> >> do.
> >> newY =. newY, ','
> >> i =. i + 2
> >> end.
> >> else.
> >> newY =. newY, i { y
> >> i =. i + 1
> >> end.
> >> end.
> >> newY
> >> )
> >>
> >> There must be a better way to do this but I can't quite figure it out.
> >>
> >> Thanks in advance,
> >> Mark
> >> ----------------------------------------------------------------------
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> >>
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