On Mon, Aug 30, 2010 at 11:59 AM, gary ng <[email protected]> wrote:
> On Sun, Aug 29, 2010 at 7:44 PM, Henry Rich <[email protected]> wrote:
>> i.&1@:~: is backed by special code, so this could be written as
>> }.~ 0&(i.&1@:~:)
> Hi, do you mind to guide me through a bit ?
>
> I kind of understand what you are trying to do but fail to follow
>
> 0&(i&1@:~:)
0&(i.&1@:~:) 0 0 2 0
2
0&(i.&1@:~:) 0 0 9 0
2
0 (i.&1@:~:) 0 0 9 0
2
(i.&1) 0 ~: 0 0 9 0
2
(0 ~: 0 0 9 0) i.1
2
And, of course:
0 ~: 0 0 9 0
0 0 1 0
--
Raul
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