On Tue, Sep 28, 2010 at 8:29 AM, Raul Miller <[email protected]> wrote:
> Factor=: monad define
> tree=: ({.tree),(<1 0 2{tree),3}.tree
> stack=: ({.stack),(classify '0'),3}.stack
> )
That is wrong. I sent a fix to Dan (along with some stylistic changes),
but forgot to post it here:
Factor=: monad define
tree=: ({.tree),(<2 A.0;1 2{tree),3}.tree
stack=: ({.stack),(classify '0'),3}.stack
)
Note that I have overloaded the "end of stream" token. I am
using an asterisk, which also happens to be the multiplication
symbol. So I can use incorporate the first element when
I need to multiply.
But it's not the first element on the stack I need to use, it's
the first word that I need to use -- when I need to multiply,
that first word might not even be on the stack.
On a related note, when inspecting the partially completed
parse tree, I find this sentence to be useful:
tree {L:0 _ words
Also useful, for my debugging, has been placing an smoutput
on the rule=: line in eval.
--
Raul
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