Thanks.

R.E. Boss


> -----Oorspronkelijk bericht-----
> Van: [email protected] [mailto:programming-
> [email protected]] Namens Marshall Lochbaum
> Verzonden: vrijdag 8 oktober 2010 22:52
> Aan: 'Programming forum'
> Onderwerp: Re: [Jprogramming] Puzzle: line-circle/sphere intersection
> 
> The last line should be R>: ... . Otherwise you just test whether R is
> greater than 1.
> 
> Marshall
> 
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]] On Behalf Of R.E. Boss
> Sent: Friday, October 08, 2010 4:39 AM
> To: 'Programming forum'
> Subject: Re: [Jprogramming] Puzzle: line-circle/sphere intersection
> 
> intrsct=: 4 : 0
>  R =. x
>  'C S E'=.y
>  t=. -(S-C) (+/@:* % ] +/@:* ]) E-S
>  P=. S + t * E - S    NB. perihelion
>  R>= +/&.:*: (-&C) (S,P,:E) {~ (0 < t) + 1 < t
> )
> 
>    2 intrsct 0 0 0;2 1 1;2 2 2
> 1
> 
> 
> R.E. Boss
> 
> 
> -----Oorspronkelijk bericht-----
> Van: [email protected]
> [mailto:[email protected]] Namens R.E. Boss
> Verzonden: donderdag 7 oktober 2010 13:52
> Aan: 'Programming forum'
> Onderwerp: Re: [Jprogramming] Puzzle: line-circle/sphere intersection
> 
> That was bad reading from my side.
> The formulas should be:
> 
> ((S-C)<R)*.((E-C)<R) -...@+. ((S-C)>R)*.((E-C)>R)
> 
> D=: +&.*:/"1 (S,:E)-"1 C
> 
> (D<R) -...@+.&(*./) D>R
> 
> Apart from that, the mathematics is not correct either. I will give it
> another thought.
> 
> 
> R.E. Boss
> 
> 
> > -----Oorspronkelijk bericht-----
> > Van: [email protected] [mailto:programming-
> > [email protected]] Namens Bo Jacoby
> > Verzonden: donderdag 7 oktober 2010 13:02
> > Aan: Programming forum
> > Onderwerp: Re: [Jprogramming] Puzzle: line-circle/sphere intersection
> >
> > Hello Boss.
> >
> > I do not understand your notation. Henry wrote "startpoint S and
> > endpoint E". You wrote "endpoints A and B", but you use E in your
> pseudo
> code.
> > Please explain.
> >
> > It seems to me that you must compute the distances (s) from C to S,
> > (e) from C to E and (p) from C to the closest point P, (the
> > perihelion), and you must determine (b) if P is between S and E.
> > Intersection occurs if (s<R and e>R) or (s>R and e<R) or (b and p<R
> and
> (s>R or e>R)).
> >
> > --- Den tors 7/10/10 skrev R.E. Boss <[email protected]>:
> >
> > Fra: R.E. Boss <[email protected]>
> > Emne: Re: [Jprogramming] Puzzle: line-circle/sphere intersection
> > Til: "'Programming forum'" <[email protected]>
> > Dato: torsdag 7. oktober 2010 09.49
> >
> > Since the word 'intersect' is used, I assume you mean the boundary of
> > the circle/sphere (and not the area), so that a line segment which is
> > completely inside is not intersecting. One point at the boundary
> means
> > intersecting, I assume.
> > So the segment is not intersecting if and only if it is completely
> > inside or completely outside the circle/sphere.
> >
> >
> > If the line segment is given by the endpoints A and B, the pseudo
> code
> > is rather straightforward:
> >
> > ((A-E)<R)*.((B-E)<R) -...@+. ((A-E)>R)*.((B-E)>R)
> >
> > so ones gets
> >
> > D=: +&.*:/"1 (A,:B)-"1 E
> >
> > (D<R) -...@+.&(*./) D>R
> >
> > (untested)
> >
> >
> > R.E. Boss
> >
> >
> > > -----Oorspronkelijk bericht-----
> > > Van: [email protected] [mailto:programming-
> > > [email protected]] Namens Henry Rich
> > > Verzonden: woensdag 6 oktober 2010 22:54
> > > Aan: Programming forum
> > > Onderwerp: [Jprogramming] Puzzle: line-circle/sphere intersection
> > >
> > > Given circle/sphere with center C and radius R, and a line-segment
> > > with startpoint S and endpoint E, write the J code to tell whether
> > > the line-segment intersects the circle/sphere.
> > >
> > > R is an atom, the rest are lists with 2 or 3 atoms.
> > >
> > > This problem arises in collision detection for games and
> simulators,
> > > or if you are trying to see whether a path intersects a round
> obstacle.
> > >
> > > I found a solution whose brevity surprised me.
> > >
> > > Henry Rich
> > > -------------------------------------------------------------------
> -
> > > -- For information about J forums see
> > > http://www.jsoftware.com/forums.htm
> >
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> >
> >
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