OK, I will refine my approach. To tell you the truth my example is
something I hacked together from a larger project.
One thing I'd like to look at is the COM documentation. It might explain
things as to why, upon instantiation, you must perform Quit(). I don't
get that.
Martin Pelletier
On 2010-10-13 00:03, Alex Rufon wrote:
> Just a side note, your initialize() function would fail if debug == false. It
> has something to do with the requirement of J602 that a Window must be
> created to initialize J properly. Hence the code:
> If Me.debug Then
> jScript += vbCrLf& _
> "0!:0<BINPATH,'\\profile.ijs'"& vbCrLf& _
> "wd 'pn *Session Server'" //<<-- NOTE on THIS CODE
> jObject.Log(1)
> jObject.Show(1)
> Else
> jObject.Do("11!:0'pc Session;cc e editijx;'") //<<-- NOTE on THIS
> CODE
> jObject.Log(0)
> jObject.Show(0)
> End If
>
> In my sample code in
> http://www.jsoftware.com/jwiki/Guides/J%20VB.NET#Initialization
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